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Query SQL -- help !!!Hi, the next query returns 11 coloumns with null and string value.
SELECT (SELECT [85.32.201.81].MessageText WHERE ([85.32.201.81].MessageText LIKE '%Rule=1')) AS Rule1, (SELECT [85.32.201.81].MessageText WHERE ([85.32.201.81].MessageText LIKE '%Rule=2')) AS Rule2, (SELECT [85.32.201.81].MessageText WHERE ([85.32.201.81].MessageText LIKE '%Rule=3')) AS Rule3, (SELECT [85.32.201.81].MessageText WHERE ([85.32.201.81].MessageText LIKE '%Rule=4')) AS Rule4, (SELECT [85.32.201.81].MessageText WHERE ([85.32.201.81].MessageText LIKE '%Rule=5')) AS Rule5, (SELECT [85.32.201.81].MessageText WHERE ([85.32.201.81].MessageText LIKE '%Rule=6')) AS Rule6, (SELECT [85.32.201.81].MessageText WHERE ([85.32.201.81].MessageText LIKE '%Rule=7')) AS Rule7, (SELECT [85.32.201.81].MessageText WHERE ([85.32.201.81].MessageText LIKE '%Rule=8')) AS Rule8, (SELECT [85.32.201.81].MessageText WHERE ([85.32.201.81].MessageText LIKE '%Rule=9')) AS Rule9, (SELECT [85.32.201.81].MessageText WHERE ([85.32.201.81].MessageText LIKE '%Rule=10')) AS Rule10, (SELECT [85.32.201.81].MessageText WHERE ([85.32.201.81].MessageText LIKE '%Rule=11')) AS Rule11 FROM [85.32.201.81] WHERE (MessageText LIKE '%Rule=%') The question is how to count the number of entries of each coloumn ?? I want something like this: Rule1 Rule2 Rule3 ...... Rule11 7 25 2 57 Thanks a lot Stefano |
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