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  #1 (permalink)  
Old 09-12-2006, 05:59 PM
sharad
 
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Default SQL 92 dialect question:

How do I implement LastIndexOf functionality in SQLServer 2000?


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  #2 (permalink)  
Old 10-08-2006, 07:00 AM
Dimitar
 
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Default MS SQL answer. Re: How do I implement LastIndexOf functionality in SQLServer 2000?

SELECT case when charindex('12',s) =0 then 0 else length(s)-charindex(reverse('12'),reverse(s)) end AS lastIndexOf, s FROM t;
The above was not tested.
The above finds the last index of '12' in column 's' of table 't'.
Hope this helps.
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Old 05-11-2007, 07:13 PM
Adam
 
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Default ANY answer. Re: How do I implement LastIndexOf functionality in SQLServer 2000?

This might be a little "simpler"

(CHARINDEX('.',REVERSE(ContactEmail)) > 4)

This checks for the last index of a period in an email address thats position is not more than 3 places in

meme.email@domain.ccom would "fail", but meme.email@domain.com and meme.email@domain.ca would "pass"
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  #4 (permalink)  
Old 05-12-2007, 07:18 PM
Dimitar
 
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Default ANY answer. Re: How do I implement LastIndexOf functionality in SQLServer 2000?

Adam,

The solution you posted works only when the string to search consists of exactly one character.
When a longer string is needed you need to reverse both, as in my answer #1.

Don't you agree?

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